ZeroJudge D260: Behold my quadrangle

UVa 11455 – Behold my quadrangle

Every square is a rectangle, every rectangle is a quadrilateral, and every quadrilateral has four sides. However, not all rectangles are squares, not all quadrilaterals are rectangles, and not every four sides can form a quadrilateral.

Problem: Given the lengths of four sides, you must determine if they can form a square. If not, determine if they can form a rectangle. If not, determine if they can form a quadrilateral.

Sample Inputs/Outputs

Sample Input(s)Sample Output(s)
The first line of input contains an integer representing the number of test cases.
Each test case consists of a single line containing four positive integers ranging from 0 to 230.		For each test case, if the given lengths can form a square, rectangle, quadrangle, or none of them, respectively, output 'square', 'rectangle', 'quadrangle', or 'banana' on a single line.
4
10 8 7 6
9 1 9 1
29 29 29 29
5 12 30 7		quadrangle
rectangle
square
banana

Thought Process

Store the four side lengths into a vector and sort them.

Square: All four sides are equal in length.

Rectangle: The first two sides are equal in length, and the last two sides are equal in length.

Quadrilateral: The sum of the first three sides is greater than the fourth side.

Non-quadrilateral: Otherwise.

Sample Code－ZeroJudge D260: Behold my quadrangle

#include <iostream>
#include <vector>
#include <algorithm>
using namespace std;

int main() {
    cin.sync_with_stdio(0);
    cin.tie(0);
    int N;
    cin >> N;
    for (int i = 0; i<N; i++)
    {
        vector<int>num;
        bool zero = false;
        for (int j = 0; j<4; j++)
        {
            int tmp;
            cin >> tmp;
            num.push_back(tmp);
            if (tmp == 0) zero = true;
        }
        if (zero)
        {
            cout << "banana\n";
            continue;
        }
        sort(num.begin(), num.end());
        if (num[0] == num[1] && num[1] == num[2] && num[2] == num[3]) cout << "square\n";
        else if (num[0] == num[1] && num[2] == num[3]) cout << "rectangle\n";
        else if (num[0] + num[1] + num[2] > num[3]) cout << "quadrangle\n";
        else cout << "banana\n";
    }
}

//ZeroJudge D260
//Dr. SeanXD
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